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Q: Find 2 consecutive numbers whose sum is 123?

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61 & 62

The numbers are 39, 41 and 43.

They are 61+62 = 123

between which two consecutive integers does the square root lie 123

61 and 62.

The numbers are 40, 41 and 42.

It can be, if the numbers are the right ones.

123/3 - 2, 123/3 and 123/3 + 2 ie 39, 41 and 43.

They are 40, 41 and 42.

The numbers are 122, 123, 124 as well as 121, 123, 125.

The numbers are 39, 41 and 43.

The integers are 40, 41 and 42.

"Average" number must be 369/3 ie 123 so numbers are 122, 123 and 124

The numbers are 121, 122 and 123.

There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.

121 123 125 127

122, 123, 124, 125, 126. The only way for the mean of 5 consecutive numbers to be 124 is if the median is also 124.

39,41,43! Ya

123, 234, 345, 456, 567, 678 sorry if this wasn't what you were looking for but consecutive numbers are just numbers that come next to each other there isn't really a pattern.

You are told that:a + b + c = 123You are also told that:b = a + 1c = a + 2Therefore:a + (a + 1) + (a + 2) = 1233a + 3 = 1233a = 120a = 40Therefore, the numbers are 40, 41 and 42.

123

There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.

They are: -39 -41 -43 = -123

The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123

You need at least two numbers to find a GCF.

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